If (frac{3^{(1-n)}}{9^{-2n}}=frac{1}{9}) find n
-
A.
(-frac{3}{2}) -
B.
(frac{1}{3}) -
C.
-1 -
D.
-3
Correct Answer: Option C
Explanation
(frac{3^{(1-n)}}{9^{-2n}}=frac{1}{9}\
3^{1-n}times 3^{-2(-2n)} = 3^{-2}\
1-n-2(-2n)= -2\
1-n+4n=-2\
n=-1)
(frac{3^{(1-n)}}{9^{-2n}}=frac{1}{9}\
3^{1-n}times 3^{-2(-2n)} = 3^{-2}\
1-n-2(-2n)= -2\
1-n+4n=-2\
n=-1)