In the diagram above, |QR| = 12cm and |QS| = 10cm. If ∠PQR = 90°, ∠RSQ = 90° and PSQ is a straight line, find |PS|
-
A.
3.3cm -
B.
4.4cm -
C.
5cm -
D.
5.5cm -
E.
6.6cm
Correct Answer: Option B
Explanation
(frac{PQ}{RQ} = frac{RQ}{SQ}) (Similar triangles)
(therefore frac{PS + 10}{12} = frac{12}{10})
(10 (PS + 10) = 12 times 12)
(10 PS + 100 = 144 implies 10 PS = 44)
(PS = 4.4 cm)