If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is
-
A.
o -
B.
2/15 -
C.
11/15 -
D.
4/15 -
E.
1
Correct Answer: Option B
Explanation
P(X (cap) Y) = (frac{1}{3} times frac{2}{5})
= (frac{2}{15})
If events X and Y are mutually exclusive, . P(X) = 1/3 and P(Y) = 2/5, P(X∩Y) is
P(X (cap) Y) = (frac{1}{3} times frac{2}{5})
= (frac{2}{15})