If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is
-
A.
o -
B.
2/15 -
C.
4/14 -
D.
11/15 -
E.
1
Correct Answer: Option D
Explanation
P(X (cup) Y) = (frac{1}{3} + frac{2}{5})
= (frac{11}{15})
If events X and Y are mutually exclusive, P(X) = 1/3 and P(Y) = 2/5, P(X∪Y) is
P(X (cup) Y) = (frac{1}{3} + frac{2}{5})
= (frac{11}{15})