simple harmonic oscillator has a period of 0.02s and amplitude of 0.25m. Calculate the speed in ms-1 at the centre of the oscillation
-
A.
125(pi) -
B.
25.00(pi) -
C.
100.00 (pi) -
D.
400.00(pi)
Correct Answer: Option B
Explanation
V = WX = (frac{2pi times 0.25}{0.02} = 25pi)