In the diagram given, the current passing through the 6(Omega) resistor is 1.5A. Calculate the terminal p.d. of the battery in the diagram
-
A.
7.50V -
B.
9.00V -
C.
10.80V -
D.
1.25V
Correct Answer: Option C
Explanation
C.V = 1R1 + 1R2/sub>
= (1.2 1.5) + (1.5 6)
= 1.8 + 9
= 10.80V