Ice of mass 10g at 5°C was completely converted to water at 0°C, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg(^{-1})K(^{-1}), specific latent heat of fusion of ice = 336 Jg(^{-1})]
-
A.
105J -
B.
3255J -
C.
3465J -
D.
16821J
Correct Answer: Option C
Explanation
Q = ML + MC(theta)
= 10 x 335 + 10 x 2.1 x 5
= 3465J