From the diagram above, calculate the energy stored in the capacitor
-
A.
4.0 x 10(^{-2})J -
B.
4.0 x 10(^{-4})J -
C.
8.0 x 10(^{-4})J -
D.
8.0 x 10(^{-2})J
Correct Answer: Option B
Explanation
c = 8µF, v = 10v
Energy stored = (frac{1}{2}) cv2
= (frac{1}{2}) × (8 × 10− 6) × 102
= 4 × 10(^{-4})
There is an explanation video available below.