Eight alpha decays and six beta decays are necessary before an atom of 2 (^{238}_{92}U) achieves stability. The final product in the chain has an atomic number of
-
A.
70 -
B.
78 -
C.
82 -
D.
90
Correct Answer: Option C
Explanation
U (to) 8((^{4}_{2}He)) + 6((^{0}_{-1}e)) + (^{b}_{a}X)
92 = (8 X 2) + (6 X -1) + a
a = 82