An object of volume 400cm3 and 2.5gcm-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm-3)
-
A.
1200g -
B.
1000g -
C.
800g -
D.
400g
Correct Answer: Option C
Explanation
Mass = density x volume
400 x 2.5 = 1000g
Loss in mass = volume x density
= (frac{400}{2}) x 1 = 200g
Reading on spring balance = 1000 – 200g = 800g