An electric lamp rated 120W is used on a 240Vrms, calculate the resistance of its filament
-
A.
480(Omega) -
B.
360(Omega) -
C.
60(Omega) -
D.
2(Omega)
Correct Answer: Option A
Explanation
R = (frac{V^2}{P} = frac{240^2}{120} = 480Omega)
R = (frac{V^2}{P} = frac{240^2}{120} = 480Omega)