An alternating current with a peak value of 5A passes through a resistor of resistance 10Ω. Calculate the rate at which energy is dissipated in the resistor
-
A.
250W -
B.
125W -
C.
50W -
D.
35.4W -
E.
12.5W
Correct Answer: Option A
Explanation
P=(I^2R= 25times 10=250W)