A substance has half of 3 min. After 6 min, the count rate was observed to be 400. What was its count rate at zero time?
-
A.
1600 -
B.
1200 -
C.
200 -
D.
2400
Correct Answer: Option A
Explanation
Let the count rate at zero time be N
N (frac{3 min}{to}) (frac{N}{2}) (frac{3 min}{to}) (frac{N}{4})
(frac{N}{4})
= 400
N = (frac{400}{N/4}) x N
= 1600
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