A potential difference of 12V is applied across the ends of a 6(Omega) resistor for 10 minutes. Determine the quantity of heat generated
-
A.
720J -
B.
1200J -
C.
14400J -
D.
43200J
Correct Answer: Option C
Explanation
Q = (frac{V^2 t}{R}
= frac{12^2 times 10 times 60}{6})
= 14400J