A particle moves in a circular orbit of radius 0.02m. If the speed of the particle is 0.88ms-1, calculate its frequency in cycles per second
-
A.
2.0Hz -
B.
7.0Hz -
C.
8.8Hz -
D.
14.0Hz -
E.
17.6Hz
Correct Answer: Option B
Explanation
W = (frac{v}{r})
= (frac{0.88}{0.02}) = 44 rad/s
2(pi)F = W = 44
F = (frac{44}{2 times 3.142})
= 7Hz