A galvanometer of internal resistance 50(Omega) and full scale deflection of 20 mA is converted into a voltmeter by connecting a resistor of resistance 1950(Omega) in series to it. Calculate the maximum voltage that can be read by the voltmeter
-
A.
20V -
B.
30V -
C.
38V -
D.
40V
Correct Answer: Option D
Explanation
V = IR1 + IR2
= 0.02 x 50 + 0.02 x 1950 = 40V