A cell of internal resistance 2 π supplies current to a 6 π resistor. The efficiency of the cell is
-
A.
12.0% -
B.
25.0% -
C.
33.3% -
D.
75.0%
Correct Answer: Option C
Explanation
Internal resistance determine the maximum current that can be supplied
Efficiency = (frac{r}{R}) × 100
= (frac{2}{6}) × 100
= 33.3%
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