A cell of emf 1.5V is connected in series with a 1Ω resistor and a current of 0.3A flows through the resistor. Find the internal resistance of the cell
-
A.
4.0Ω -
B.
3.0Ω -
C.
1.5Ω -
D.
1.0Ω
Correct Answer: Option A
Explanation
r = (frac{E}{I} – R)
r = (frac{1.5}{0.3} – 1)
r = 4(Omega)
There is an explanation video available below.