A body of volume 0.046m3 is immersed in a liquid of density 980kgm-3 with (frac{3}{4}) of its volume submerged. Calculate the upthrust on the body. [g = 10ms-2]
-
A.
11.27N -
B.
33.81N -
C.
112.70N -
D.
338.10N
Correct Answer: Option D
Explanation
M = D x V
= 980 x 0.046 x (frac{3}{4}) = 33.81kg
upthrust = mg = 33.81 x 10
= 338.1N