A body accelerates uniformly from rest at (2ms^{-2}). Calculate the velocity after traveling 9m
-
A.
36(ms^{-1}) -
B.
18(ms^{-1}) -
C.
6(ms^{-1}) -
D.
4.5(ms^{-1}) -
E.
4.24(ms^{-1})
Correct Answer: Option C
Explanation
(V^2= U^2+2as) =(0+ 2times 2ms^{-2}times 9 =36ms^{-1}) thus
V=(sqrt{36m^2s^{-2}}) = (6ms^{-1})