A battery of emf 24V and internal resistance 4Ω is connected to a resistor of 32Ω. What is the terminal p.d of the battery?
-
A.
24.0V -
B.
21.3V -
C.
16.0V -
D.
2.7V -
E.
2.0V
Correct Answer: Option B
Explanation
E = V + Ir
V = E- Ir
V = 24 – {(24/36) x 4}
V = 21.3V