A battery of e.m.f 10V an internal resistance 2Ω is connected to a resistance of 6Ω. Calculate the p.d
-
A.
8.75V -
B.
7.50V -
C.
5V -
D.
2.50V -
E.
1.25V
Correct Answer: Option B
Explanation
V = E – Ir = 10V – (frac{10 times 2}{8}) = 7.5V
V = E – Ir = 10V – (frac{10 times 2}{8}) = 7.5V