A 5kg block is released from rest on a smooth plane inclined at an angle of 30o to the horizontal. What is the acceleration down the plane? [g = 10ms-2]
-
A.
5.0 ms-2 -
B.
5.8 ms-2 -
C.
8.7 ms-2 -
D.
25.0 ms-2
Correct Answer: Option A
Explanation
ma = mgsin(theta)
a = (frac{5 {times} 10 {times} sin30}{t})
a = 5ms2