A 15 (mu F) capacitor is connected to a 240V, 50Hz ac. source. Calculate the reactance of the capacitance [(pi = 3.142)]
-
A.
16(Omega) -
B.
68(Omega) -
C.
106(Omega) -
D.
212(Omega)
Correct Answer: Option D
Explanation
(X_c = frac{1}{2 pi fc})
= 2 x 3.142 x 50 x 15 x 10-6
= 212.179(Omega)