250g of lead at 170oC is dropped into 100g of water at 0oC. If the final temperature is 12oC, the specific heat of lead is (specific heat of water is 4,200J/kgoC)
-
A.
39.5J/kgoC -
B.
50.4J/kgoC -
C.
127.6J/kgoC -
D.
154.6J/kgoC -
E.
173.4J/kgoC
Correct Answer: Option C
Explanation
Heat lost = heat gained
0.25 x C1 x (170 – 12) = 0.1 x 4200 x (12 – 0)
C1 = 127.6J/kgoC