What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?
- A.y = –χ + 6
- B.y = –χ – 6
- C.y = χ + 6
- D.y = χ – 6
Correct Answer: Option A
Explanation
Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1
Gradient bisector = -1
Equation of perpendicular bisector y – y1 = m(χ – χ1y – 4 = –χ + 2y = -χ + 6