What is the least possible value of (frac{9}{1 + 2x^2}) if 0 (geq) x (geq) 2?
-
A.
9 -
B.
5 -
C.
1 -
D.
2
Correct Answer: Option C
Explanation
0 (geq) x (geq) 2 (to) 0, 1, 2
If x = 0, (frac{9}{1 + 2x^2})
(frac{9}{1 + 2(0)^2}) = (frac{9}{1})
= 3
If x = 2, (frac{9}{1 + 2(1)^2})
= (frac{9}{3})
= 3
If x = 2, (frac{9}{1 + 2(2)^2})
= (frac{9}{9})
= 1
The least value of (frac{9}{1 + 2x^2}) is 1 when x = 2