The sum of (3frac{7}{8}) and (1frac{1}{3}) is less than the difference between (frac{1}{8}) and (1frac{2}{3}) by:
-
A.
3(frac{2}{3}) -
B.
5(frac{1}{4}) -
C.
6(frac{1}{2}) -
D.
8 -
E.
8(frac{1}{8})
Correct Answer: Option A
Explanation
(3frac{7}{8} + 1frac{1}{3} = 4frac{21 + 8}{24})
= (4frac{29}{24})
(equiv 5frac{5}{24})
(1frac{2}{3} – frac{1}{8} = frac{5}{3} – frac{1}{8})
= (frac{40 – 3}{24})
= (frac{37}{24})
(5frac{5}{24} – frac{37}{24} = frac{125}{24} – frac{37}{24})
= (frac{88}{24})
= 3(frac{2}{3})