The roots of a quadratic equation are (frac{-1}{2}) and (frac{2}{3}). Find the equation.
-
A.
(6x^2 – x + 2 = 0) -
B.
(6x^2 – x – 2 = 0) -
C.
(6x^2 + x – 2 = 0) -
D.
(6x^2 + x + 2 = 0)
Correct Answer: Option B
Explanation
(x + (frac{1}{2})) (n – (frac{2}{3}))
(x^2 – frac{2}{3^x} + frac{x}{2} – frac{1}{3})
(6x^2 – 4n + 3n – 2 = 0)
(6x^2 – x – 2 = 0)