The perimeter of a sector of a circle of radius 4cm is ((pi + 8))cm. Calculate the anle of the sector
-
A.
45o -
B.
60o -
C.
75o -
D.
90o
Correct Answer: Option A
Explanation
Perimeter of sector = 2r + (frac{theta}{360^o} times 2pi r)
(pi + 8 = 2 times 4 + frac{theta}{3360^o} times 2 pi times 4)
(pi + 8 + frac{theta}{360^o} times 8 pi)
P + 8 – 8 = (frac{theta pi}{456o})
(pi = frac{theta pi}{45^o})
(theta pi = 45^o)