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The nth term of a sequence is Tn = 5 + (n – 1)2. Evaluate…

The nth term of a sequence is Tn = 5 + (n – 1)2. Evaluate T4 – T6
  • A.
    30
  • B.
    16
  • C.
    -16
  • D.
    -30
Correct Answer: Option C
Explanation

T4 = 5 + (4 – 1)2; where n = 4
= 5 + (3)2 = 5 + 9
= 14
T = 5 + (6 – 1)2
where n = 6
= 5 + (5)2
= 5 + 25 = 30
T4 + T6 = 14 – 30
= -16