The nth term of a sequence is Tn = 5 + (n – 1)2. Evaluate T4 – T6
-
A.
30 -
B.
16 -
C.
-16 -
D.
-30
Correct Answer: Option C
Explanation
T4 = 5 + (4 – 1)2; where n = 4
= 5 + (3)2 = 5 + 9
= 14
T = 5 + (6 – 1)2
where n = 6
= 5 + (5)2
= 5 + 25 = 30
T4 + T6 = 14 – 30
= -16