-
A.
360o -
B.
252o -
C.
246o -
D.
234o
Correct Answer: Option B
Explanation
Let 0 = angle of the minor sector
angle of the major sector = 360 – (theta)(angle at a point)
2 (pi r) = 54 + 126(i.e circumference of minor and major arc)
2(pi r = 180^o)
r = (frac{180}{2pi}) = (frac{90}{pi})
Lenght of ninor arc
= (frac{theta}{360} times 2 pi r)
54 = (frac{theta}{360} times 3 pi r)
(theta = frac{360 times 54}{2 pi r})
but r = (frac{90}{pi}) substituting (frac{90}{pi}) for r
(theta = frac{360 times 54 times pi}{2 times pi times 90})
(theta = 2 times 54 = 108^o)
angle of the major sector = 360 – 108o
= 252o