Make x the subject of the relation d = (sqrt{frac{6}{x} – frac{y}{2}})
-
A.
x = (frac{6 + 12}{d^2 + y}) -
B.
x = (frac{12}{d^2 – y}) -
C.
x = (frac{12}{y} – 2d^2) -
D.
x = (frac{12}{2d^2 – y})
Correct Answer: Option A
Explanation
d = (sqrt{frac{6}{x} – frac{y}{2}})
(d^2 = frac{6}{x} – frac{y}{2})
(2xd^2 = 12 – xy)
(2xd^2 + xy = 12)
x = (frac{6 + 12}{d^2 + y})