Make S the subject of the relation
p = s + (frac{sm^2}{nr})
-
A.
s = (frac{nrp}{nr + m^2}) -
B.
s = nr + (frac{m^2}{mrp}) -
C.
s = (frac{nrp}{mr}) + m2 -
D.
s = (frac{nrp}{nr}) + m2
Correct Answer: Option A
Explanation
p = s + (frac{sm^2}{nr})
p = s + ( 1 + (frac{m^2}{nr}))
p = s (1 + (frac{nr + m^2}{nr}))
nr × p = s (nr + m2)
s = (frac{nrp}{nr + m^2})
There is an explanation video available below.