M and N are two subsets of the universal set (U). If n(U) = 48, n(M) = 20, n(N) = 30 and n(MUN) = 40, find n(M (cap) N)
-
A.
18 -
B.
20 -
C.
30 -
D.
38
Correct Answer: Option D
Explanation
Let n(M (cup) N ) = x
Then 20 – x + x + 30
– x = n(M (cup) N)
50 – x = 40
50 – 40 = x
10 = x
x = 10
Hence, n(M (cupN)’ = 8 + (20 – 10) + (30 + 10)
= 8 + 10 + 20
= 38