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In the diagram, NQ//TS,

In the diagram, NQ//TS, <RTS = 50(^o) and <PRT = 100(^o). Find the value of <NPR

  • A.
    110(^o)
  • B.
    130(^o)
  • C.
    140(^o)
  • D.
    150(^o)
Correct Answer: Option B
Explanation

< TSR = 180 – (80 + 50)

= 180 – (130)

= 50(^o)

< QPR = < TSR corresponding < s

< NPR + QPR = < NPR

180(^o) – < QPR = < NPR

180(^o) – 50 = < NPR

< NPR = 130(^o)