In the diagram, NQ//TS, <RTS = 50(^o) and <PRT = 100(^o). Find the value of <NPR
-
A.
110(^o) -
B.
130(^o) -
C.
140(^o) -
D.
150(^o)
Correct Answer: Option B
Explanation
< TSR = 180 – (80 + 50)
= 180 – (130)
= 50(^o)
< QPR = < TSR corresponding < s
< NPR + QPR = < NPR
180(^o) – < QPR = < NPR
180(^o) – 50 = < NPR
< NPR = 130(^o)