In the diagram, KS is a tangent to the circle centre O at R and ∠ROQ = 80o. Find ∠QRS.
-
A.
90o -
B.
80o -
C.
50o -
D.
40o
Correct Answer: Option C
Explanation
∠QRS = ∠RPQ (theorem: angle in the alternate segment are equal)
∠RPQ = 50o
∠QRS = 50o
∠QRS = ∠RPQ (theorem: angle in the alternate segment are equal)
∠RPQ = 50o
∠QRS = 50o