In the diagram above, |PQ| = |PR| = |RS| and ∠RPS = 32°. Find the value of ∠QPR
-
A.
72o -
B.
64o -
C.
52o -
D.
32o -
E.
26o
Correct Answer: Option C
Explanation
From the figure, < PSR = 32° (base angles of an isos. triangle)
(therefore) < PRS = 180° – (32° + 32°) = 116° (sum of angles in a triangle)
< QRP = 180° – 116° = 64° (angle on a straight line)
< PQR = 64° (base angles of an isos. triangle)
< QPR = 180° – (64° + 64°) = 52°