In the diagram above, ATR is a tangent at the point T to the circle center O, if ∠TOB = 145°, find ∠TAO
-
A.
20o -
B.
35o -
C.
45o -
D.
55o -
E.
65o
Correct Answer: Option D
Explanation
From the figure, < ATO = 90°
< AOT = 180° – 145° = 35°
(therefore) < TAO = 180° – (90° + 35°)
= 55° (sum of angle in a triangle)