If two graphs Y = px2 + q and y = 2x2 − 1 intersect at x =2, find the value of p in terms of q
-
A.
q − (frac{8}{7}) -
B.
7 − (frac{q}{4}) -
C.
8 − (frac{q}{2}) -
D.
7 + (frac{q}{8})
Correct Answer: Option B
Explanation
Y = Px2 + q
Y = 2x2 – 1
Px2 + q = 2x2 – 1
Px2 = 2x2 – 1 – q
p = (frac{2x^2 – 1 – q}{x^2})
at x = 2
P = (frac{2(2)^2 – 1 – q}{2^2})
= (frac{2(4) – 1 -q}{4})
= (frac{8 – 1 – q}{4})
P = (frac{7 – q}{4})
There is an explanation video available below.