If sin( theta ) = K find tan(theta), 0° (leq) (theta) (leq) 90°.
-
A.
1-K -
B.
( frac{k}{k – 1} ) -
C.
( frac{k}{sqrt{1 – k^2}} ) -
D.
( frac{k}{1 – k} ) -
E.
( frac{k}{sqrt{ k^2 – 1}} )
Correct Answer: Option C
Explanation
(sin theta = frac{k}{1})
(implies 1^2 = k^2 + adj^2)
(adj = sqrt{1 – k^2})
(therefore tan theta = frac{k}{sqrt{1 – k^2}})