If P (=left[begin{array}{cc}x+3 & x+2\ x+1 & x-1end{array}right]) evaluate x if |P| = -10

If P (=left[begin{array}{cc}x+3 & x+2\
x+1 & x-1end{array}right]) evaluate x if |P| = -10

Correct Answer: Option D

Explanation

(P=left[begin{array}{cc}x+3 & x+2\
x+1 & x-1end{array}right]) evaluate x if |P| = -10
(x+3)(x-1) – {(x+1)(x+2)} = -10
x² – x + 3x – 3 – {x² + 2x + x + 2} = -10
x² + 2x – 3 – {x² + 3x + 2} = -10
-x – 5 = -10
-5 + 10 = x
5 = x
∴x = 5