If dy/dx = 2x – 3 and y = 3 when x = 0, find y in terms of x.
-
A.
2x2 – 3x -
B.
x2 – 3x -
C.
x2 – 3x – 3 -
D.
x2 – 3x + 3
Correct Answer: Option D
Explanation
dy/dx = 2x – 3
y = ∫2x – 3 dx => y = x2 – 3x + c
3 = (0)2 – 3(0) + c
=> c = 3
Thus y = x2 – 3x + 3