If 3x(^o) 4(mod 5), find the least value of x
-
A.
1 -
B.
2 -
C.
3 -
D.
4
Correct Answer: Option C
Explanation
3x (equiv) 4(mod 5)
In modulo 5, multiples of 5 that give solution to the given equation are 5, 20, 35, 50,… but 5 will yield the leaast value of x.
Thus; 3x = 4 + 5 = 9
x = (frac{9}{3})
x = 3