If 2n = y, Find 2(^{(2 + frac{n}{3})})
-
A.
4y(^frac{1}{3}) -
B.
4y(^-3) -
C.
2y(^frac{1}{3}) -
D.
2y(^-3)
Correct Answer: Option A
Explanation
If 2n = y,
then, 2(^{(2 + frac{n}{3})}) = 22 x 2(^frac{n}{3})
= 4 x (2n)(^{frac{1}{3}})
But y = 2n, hence
2(^{(2 + frac{n}{3})}) = 4 x y(^{frac{1}{3}})
= 4y(^frac{1}{3})