From a point R, 300m north of P, a man walks eastwards to a place;…

From a point R, 300m north of P, a man walks eastwards to a place; Q which is 600m from P. Find the bearing of P from Q correct to the nearest degree

Correct Answer: Option D

Explanation

Cos θ = (frac{adj}{hyp})

  = (frac{300}{600})

  = 0.5

  θ = Cos – 10.5

  = 60

  ∠ RPQ = ∠ PQs

  So the bearing of P from Q is 180 + 60 = 240(^o)

  Answer is D

There is an explanation video available below.