Find the derivative of y = sin(2x(^3) + 3x – 4)
-
A.
cos (2x3 + 3x – 4) -
B.
-cos (2x3 + 3x – 4) -
C.
(6x2 + 3) cos (2x3 + 3x – 4) -
D.
-(6x2 + 3) cos (2x3 + 3x – 4)
Correct Answer: Option C
Explanation
y = sin (2x(^3) + 3x – 4)
let u = 2x(^3) + 3x – 4
∴du/dx = 6x(^2)
y = sin u
dy/du = cos u
dy/dx = du/dx * dy/du
∴dy/dx = (6x(^2) + 3) cos u
= (6x(^2) + 3)cos(2x(^3) + 3x – 4)