Evaluate (int^{frac{pi}{2}}{frac{-pi}{2}} cos x dx)
-
A.
zero -
B.
1 -
C.
2 -
D.
3
Correct Answer: Option C
Explanation
(int^{frac{pi}{2}}{frac{-pi}{2}} cos x dx = [sinx]^{frac{pi}{2}}{frac{-pi}{2}}\
=sinfrac{pi}{2} – sinfrac{-pi}{2})
= sin90 – sin-90
= sin90 – sin270
= 1 – (-1)
= 1+1
= 2