Evaluate (int_{1}^{3}(x^2 – 1)dx)
-
A.
(frac{2}{3}) -
B.
(-frac{2}{3}) -
C.
(-6frac{2}{3}) -
D.
(6frac{2}{3})
Correct Answer: Option D
Explanation
(int_{1}^{3}(x^2 – 1)dx = left[frac{1}{3}x^2 – xright] ^{3}_{1}\ =(9-3)-(frac{1}{3}-1)\ =6-left(-frac{2}{3}right)\ =6+frac{2}{3}=6frac{2}{3})