Evaluate (int_{-4}^0(1 – 2x)dx)
-
A.
-16 -
B.
-20 -
C.
20 -
D.
10
Correct Answer: Option C
Explanation
(int_{-4}^0(1 – 2x)dx=[x-x^2]_{-4}^0\= (0 – 0 + C) – (-4(-4)^2 + C)\
= C – (-4-16+C)\
= C-(-20+C)\
= C+20-C\
= 20)
(int_{-4}^0(1 – 2x)dx=[x-x^2]_{-4}^0\= (0 – 0 + C) – (-4(-4)^2 + C)\
= C – (-4-16+C)\
= C-(-20+C)\
= C+20-C\
= 20)